Analisis besi (Fe II) dg alat Titrino / Titroprocessor

Alat yg digunakan
Potentiometer = 751 GPD Titrino / Titroprocessor
Electrodes = 6.0431.100 Pt Titrode; input 1

Pereaksi
c(KMnO4) = 0.02 mol/L; D0
Sample
2 mL c[(NH4)2Fe(SO4)2] = 0.1 mol/L, acidic solution
10 mL c(H2SO4) = 0.5 mol/L
40 mL dist. Water

Rangkuman
· Determination reaction:

5 Fe2+ + MnO4- + 8 H+ → 5 Fe3+ + Mn2+ + 4 H2O

· Calculations:

Fe++=EP1*C01*C02/C00;2;g/l

Fe++ = concentration of Fe2+ in g/L
C01 = concentration of titrating agent * titer * “normality“ (0.02 * 1.000 * 5 = 0.1)
C02 = molecular mass of Iron (55.85 g/mol)

Answer

Fe++=2.065x0.1x55.85/2=5.77 g/L

EP1=2.065 mL
C00=2.000 mL

Literature
Metrohm’s Teachware on CD-ROM